Question Video: Using the Law of Sines to Calculate the Number of Triangles That Can Be Formed | Nagwa Question Video: Using the Law of Sines to Calculate the Number of Triangles That Can Be Formed | Nagwa

Question Video: Using the Law of Sines to Calculate the Number of Triangles That Can Be Formed Mathematics • Second Year of Secondary School

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For a triangle 𝐴𝐡𝐢, π‘Ž = 2 cm, 𝑏 = 5 cm, and π‘šβˆ π΄ = 35Β°. How many triangles can be formed? [A] An infinite number of triangles [B] No triangles can be formed [C] One triangle [D] Two triangles [E] Three triangles

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Video Transcript

For a triangle 𝐴𝐡𝐢, π‘Ž is equal to two centimeters, 𝑏 is equal to five centimeters, and the measure of angle 𝐴 is 35 degrees. How many triangles can be formed? Is it (A) an infinite number of triangles? (B) No triangles can be formed. (C) One triangle. (D) Two triangles. Or (E) three triangles.

We will begin by trying to sketch the triangle 𝐴𝐡𝐢 from the measurements given. We are told that the measure of angle 𝐴 is 35 degrees and side lengths π‘Ž and 𝑏 are equal to two centimeters and five centimeters, respectively. From the initial information, it appears that it may be possible to sketch at least one triangle.

In order to try and prove this, let’s recall the law of sines. This states that sin 𝐴 over π‘Ž is equal to sin 𝐡 over 𝑏, which is equal to sin 𝐢 over 𝑐, where uppercase 𝐴, 𝐡, and 𝐢 are the measures of the three angles and lowercase π‘Ž, 𝑏, and 𝑐 are the side lengths opposite them. Substituting in the measurements given, we have sin 𝐡 over five is equal to sin of 35 degrees over two. We can multiply both sides of our equation by five. This gives us that sin 𝐡 is equal to 1.4339 and so on.

However, this is not possible, since the largest value that the sine of an angle can have is one. As there are no solutions to this equation, we can conclude that no triangles can be formed from the measurements given. And the correct answer is option (B).

An alternative method here would be to calculate the height of our triangle. We know that if angle 𝐴 is acute and side length π‘Ž is less than the height of the triangle β„Ž, then no triangles exist. As we have a right triangle, we can use the sine ratio such that sin of 35 degrees is equal to the height β„Ž over five. Multiplying through by five, we have β„Ž is equal to five multiplied by sin of 35 degrees. And to two decimal places, this is equal to 2.87. Since the height of the triangle, 2.87 centimeters, is greater than side length π‘Ž, this confirms that no triangles exist. And option (B) was indeed the correct answer.

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