Question Video: Identifying the Group to Which an Unknown Element Belongs Using Its Successive Ionization Energies | Nagwa Question Video: Identifying the Group to Which an Unknown Element Belongs Using Its Successive Ionization Energies | Nagwa

Question Video: Identifying the Group to Which an Unknown Element Belongs Using Its Successive Ionization Energies Chemistry • Second Year of Secondary School

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According to the successive ionization energies of element X shown in the table below, which group in the periodic table does element X belong to? [A] Group 1 [B] Group 2 [C] Group 3 [D] Group 4

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Video Transcript

According to the successive ionization energies of element X shown in the table below, which group in the periodic table does element X belong to? (A) Group one, (B) group two, (C) group three, or (D) group four.

In this question, we need to identify the periodic table group of element X using its successive ionization energies.

We can begin by defining the first ionization energy, which is the amount of energy needed for displacing the most loosely bound electron from an isolated gaseous atom. This equation represents the first ionization energy for a boron atom. We can see that this process generates a boron one plus cation and one electron for a set amount of energy. We can represent the second and third ionization energies with similar equations. During the second ionization energy event, a boron one plus cation loses a single electron. A boron two plus cation loses another electron during the third ionization event.

We can use these equations to understand the meaning of successive ionization energies. They are the amounts of energy needed for consecutively displacing electrons from one gaseous state element. While these first three ionization energies do increase, they are not drastically different. This is because these first three electrons removed are in the same outermost electron shell. Ionization energy values are related to the electron shell the electron being removed occupies and its distance from the nucleus.

Valence electrons, which are farthest from the nucleus, are relatively easy to remove. Core electrons are closer to the nucleus and therefore have a stronger attraction to it and require much more energy to remove. As these first three valence electrons removed were in the same electron shell, they were of similar distance away from the nucleus.

Let’s now have a look at the fourth ionization energy event for boron. At 25026 kilojoules per mole, the fourth ionization energy value is drastically different from the first three. This is because the fourth electron removed is a core electron and is much closer to the nucleus. Thus, more energy is required to displace it. The pattern of successive ionization energy values reveals details about an element’s electronic configuration and thus its place on the periodic table.

Let’s have a look at the table of ionization energies for element X to determine in which periodic table group it resides. The first three ionization energy values of element X increase but are not drastically different. There is a strikingly large increase from the third to the fourth ionization energy value. This suggests that the fourth electron removed from element X is in a core electron shell. It is likely then that element X has three valence electrons and resides in group three or 13 of the periodic table.

Therefore, the group in the periodic table that element X belongs to is answer choice (C), group three.

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